Penyelesaian dari persamaan eksponen 27^x-4.3^x+3=[⅓]^2x+5adalah ....
![]()
Penjelasan dengan langkah-langkah:
Eksponen
[tex] {27}^{x - 4} . {3}^{x + 3} = ( \frac{1}{3} ) {}^{2x + 5} \\ ( {3}^{3} ) {}^{x - 4} . {3}^{x + 3} = ( {3}^{ - 1} ) {}^{2x + 5} \\ {3}^{3x - 12} . {3}^{x + 3} = {3}^{ - 2x - 5} \\ {3}^{3x - 12 + (x + 3)} = {3}^{ - 2x - 5} \\ 3x + x - 12 + 3 = - 2x - 5 \\ 4x - 9 = - 2x - 5 \\ 4x + 2x = - 5 + 9 \\ 6x = 4 \\ x = \frac{4}{6} \\ x = \frac{2(2)}{3(2)} \\ x = \frac{2}{3} [/tex]
semoga membantu
[answer.2.content]
